In the electron distribution mnemonics the sublevels are already arranged according to increasing energy as shown below: 
1s 2s 2p 3s 3p 4s 3d 4p 5s 4d 5p 6s 4f 5d 6p 7s 5f  6d 7p
Now in writing electronic configuration we have to follow the Pauli's Exclusion Principles which states that, no two electrons can have four quantum numbers, and that orbitals can only accommodate 2 electrons with opposite spins.    Since, we only have 1 s orbital in s sublevel, only two electrons can occupy in s sublevel, and we have 3 p orbitals in p sublevel, and therefore total of 6 electrons can be accommodated in p sublevel.  In d sublevel there are 5 d orbitals, accommodating 2 electrons in each orbital there are 10 total electrons that can be accommodated in d sublevel, and in f sublevel there are 7 f orbitals and having  2 electrons each orbital, total of 14 electrons are in sublevel f.  An so we have to take note in writing electrons configuration the following:  s can have only 1 or two electrons, p can have only 1 to 6 electrons, d can have 1 to 10 electrons, and f sublevels can have 1 to 14 electrons.  
We use atomic number in writing the electron configuration, since atomic number is the number of protons at the same time the number of electrons.  Let us have an example:
What is the electron configuration of first 10 elements? 
1H has only 1 electron and so the the electron is only located at the lowest sublevel 1s.  The electron configuration is :  1s1
2He has 2 electrons. The electron configuration is 1s2
3Li :  1s2 2s1
4Be:  1s2 2s2
5B : 1s2 2s2 2p1
6C : 1s2 2s2 2p2
7N : 1s2 2s2 2p3
8O : 1s2 2s2 2p4
9F :  1s2 2s2 2p5
10Ne : 1s2 2s2 2p6
We have to take note that in writing electron configuration, electron distribution mnemonics must be followed.

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